dmcutter
Contributor
Isn't that Pascals? And if you have your ascent rate in furlongs per fortnight, I hope you have the sampling rate set in nanoseconds so it will actually give you a reading.
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If you really want to screw with someone's head, try explaining why the 5# of lead ballast only weighs 5# until they jump in the water.
If you suck the fluid into your lungs and your belly, then that inside water will counteract the outside water.
It's the old "for every action there is an equal and opposite reaction" thing. If you are in 33 ft of water and neutral, and let's assume horizontal so the pressure is equal over your whole area is equal, the column of water over you is exerting 2 atm worth of pressure on you. The water under you is exerting the same 2 atm of pressure, otherwise you would be sinking.
Technically, that 5# weighs more since it's closer to the attracting mass center, though not by much.
The OP asked a simple question. Actually, it was simple-minded coming from a diver who should know better.
Surely it will weigh less? If its at the attracting mass centre it would be weightless