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Displacement of Scooters at Depth - Spun off from the A&I Discussion about Nothernone

Discussion in 'Dive Propulsion Vehicles' started by lv2dive, Mar 28, 2019.

  1. johndiver999

    johndiver999 Manta Ray

    # of Dives: 500 - 999
    Location: Gainesville FL
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    No reread the scenario I provided, it was very explicit and was neutral (strictly for simplicity)
     
  2. Dan

    Dan Great White

    # of Dives: 500 - 999
    Location: Texas
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    Agree.

    I was just trying to say that the net weight in the water would be different if it is not neutrally buoyant.

    If an object has 2.1 kp (positive) buoyancy with internal air volume of 11 liters. The net buoyancy will be -8.9 (-11 + 2.1) kp as the case of AL80

    If an object has -3.5 kp (negative) buoyancy with internal air volume of 10 liters. The net buoyancy will be -13.5 (-19 - 3.5) kp as the case of Steel 300 bar tank.
     
  3. Dan

    Dan Great White

    # of Dives: 500 - 999
    Location: Texas
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    You did. I must have missed it. Sorry!

    I was fixated on the AL80 example few pages back, which is not neutrally buoyant.

     
    johndiver999 likes this.
  4. tursiops

    tursiops Marine Scientist and Master Instructor ScubaBoard Supporter

    # of Dives: 2,500 - 4,999
    Location: U.S. East Coast
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    I'd find your explanations more understandable and more compelling if you used proper units and not obsolete things like kp or incorrect things like L instead of l.
     
  5. Dan

    Dan Great White

    # of Dives: 500 - 999
    Location: Texas
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    I use kp because other use it here. Since we are talking about force, it's easier and less confusing to use kp than Newton. 1 kp = 1 kg force = 1 kg mass x gravity acceleration of 9.8 m/s2 = 9.8 Newton.

    Using l for liter could be mistaken as I (capital letter of i) in my too smart iPhone spellchecker. :)
     
    IncreaseMyT likes this.

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