My guess is that doing the 10' stop after teh 20 increases the off gassing rate. So you trade say 10 min of stop at 20 for 8 at 20 and 4 at 10. Doublr thr dp by going to 10 and cut the stop time in half. So 100% o2 stops the intake. if the body (deco wize) is at say 40 ft and you compare your depth of 20 vs 10 ,,,then 10 would have a higher dp and thus a faster off gassing fo the remaining system gasses. off gassing has to be pretty slow when the cells are at 30' and the body is at 20 compared to 10. On air you are on gassing and off gassing so to speek so th difference should be less than on o2. Pls no one flame me, it is only a logical guess. some other thoughts . Is your vplanner using the 30/85 gradient in its calcs? I would think that if 20 ft is your last stop and you deco to a given level it should take longer than if you last stop is 10' to get to the same given level, once again because of the larger dp causng higher higher off gas rate per the position on the 30/85 gradient line. I would think that this effect would be more pronounced with longer deco obligations since the slower tissues would become the driving factor of extended deco periods at shallower depths. kind of like using 100%o2 cuts deco time in half compared to 50% o2. Another benifit of hte 10 ft stop is that you dont have to carry so much deco gas because of the shorter total deco time. Sorry for the poor verbalization.