Don and all,
Just so you'll know, you need to use the absolute pressure in atmospheres to make the multiplication that Don makes above. I've explained this on a newer thread:
How Much CO is divable
SeaRat
John C. Ratliff, CSP, CIH, MSPH
Just so you'll know, you need to use the absolute pressure in atmospheres to make the multiplication that Don makes above. I've explained this on a newer thread:
How Much CO is divable
SeaRat
John C. Ratliff, CSP, CIH, MSPH